Section 1.3: Functions
Exercise 5
Show that the Signum Function \(f :
\mathbb{R} \to \mathbb{R}\), given by
\[
f(x) =
\begin{cases}
1, & \text{if } x > 0 \\
0, & \text{if } x = 0 \\
-1, & \text{if } x < 0
\end{cases}
\] is neither one-one nor onto.